18b^2-98=0

Solution for 18b^2-98=0 equation:

18b^2-98=0

a = 18; b = 0; c = -98;
Δ = b2-4ac
Δ = 02-4·18·(-98)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*18}=\frac{-84}{36}
=-2+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*18}=\frac{84}{36}
=2+1/3
$